Answer:
The product of the y-coordinates of the solutions is equal to 3
Step-by-step explanation:
we have
-----> equation A
------> equation B
Solve by graphing
Remember that the solutions of the system of equations are the intersection point both graphs
using a graphing tool
The solutions are the points (2,3) and (6,1)
see the attached figure
The y-coordinates of the solutions are 3 and 1
therefore
The product of the y-coordinates of the solutions is equal to
(3)(1)=3
if the diameter of a circle is 15, its radius is half that or 7.5.
Answer:
Step-by-step explanation:
In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.
The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:
The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be (). Now one has this much of the function assembled
Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following: