The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Its the third one..........
Answer:
i. 13.23
ii. 20.58
iii. 76.77
iv. 84.48
Step-by-step explanation:
Here , we are to calculate the square root of we have of the decimal numbers and correct to two decimal places.
i. √(175.01) = 13.229 = 13.23
ii. √(423.74) = 20.5849 = 20.58
iii. √(5893.27) = 76.767 = 76.77
iv. √(7136.8) = 84.4795 = 84.48
Kindly note that the approximation to two decimal places are the figures after the equal to
Answer:
I think it is the second one because -4 is the least
Step-by-step explanation:
