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3 years ago

Find interquartile range for 3,4,5,6,7

Mathematics

2 answers:

lions [1.4K]3 years ago

8 0

3, 4, 5, 6 and 7
Q 1= (3+4)/2=3.5
Q 2= (4+5)/2=4.5
Q 3=(5+6)/2=5.5
Interquartile range =Q3-Q1
=5.5-3.5
=2

worty [1.4K]3 years ago

8 0

Median: 5

Lower Quartile: 3.5

Upper Quartile: 6.5

IQR Interquartile Range: 6.5 - 3.5 = 2

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Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

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3 years ago

How many 1/3s do you need to make 3/4

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Answer:

2.25

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2 years ago

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The sum of four consecutive numbers is 230. What is the largest of these numbers

vodka [1.7K]

Answer:

n + n+1 + n+2 + n+3 = 230

4n = 224

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Step-by-step explanation:

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3 years ago

5. – 3(1 + 6r) = 14 - 7

MAVERICK [17]

Answer:

r= -1.8

Step-by-step explanation:

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$\frac{300}{ x^{2}}$

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