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3 years ago

15

After four rounds, 74 teams are eliminated from a robotics competition. There are 18 teams remaining. Write and solve an equatio

n to find the number of teams t that started the competition.

1 answer:

Mariulka [41]3 years ago

4 0

It is 92 .............

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I need help with a math question

Julli [10]

Answer:

Question 1: 4.5(10^−7)(2(10^4))

=

9/1000

(Decimal: 0.009)

Question 2:

mass of neutron/mass of electron = 2*10-24/(9*10-28)

2x10^(-24)/9x10^(-28)

d is closest.

Question 3:

4(10^3)(12(10^5))

=4000*1200000

=4*1000*12*100000

=(4*12)*(1000*100000)

=48*100000000

=4800000000

And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!

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3 0

3 years ago

HELLPPPPPPPPP WITH THE TOP THREE PLS

rodikova [14]

Answer:

9) Domain: 0≤x≤6

Range: -3≤y≤3

10) Domain: -∞≤x≤∞

Range: -∞≤y≤∞

11) Domain: -∞≤x≤∞

Range: y≥-2

13) Domain: -∞≤x≤∞

Range: -2≤y≤4

Step-by-step explanation:

9) Domain: 0≤x≤6

Range: -3≤y≤3

10) Domain: -∞<x<∞

Range: -∞<y<∞

11) Domain: -∞<x<∞

Range: y≥-2

13) I think you need to look at this one again. It looks like:

Domain: -∞<x<∞

Range: -2≤y≤4

4 0

3 years ago

Vertical line through the point (9,6)

kolezko [41]

What about it that is not a question

5 0

3 years ago

Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain

Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression $2b+b$ and $3b$ and values of b as 1, 2 and 3.

Consider first expression that is, $2b+b$ .

Substituting the value of $b=1$ ,

$2\left(1\right)+\left(1\right)=2+1=3$ ....1

Substituting the value of $b=2$ ,

$2\left(2\right)+\left(2\right)=4+2=6$ ....2

Substituting the value of $b=3$ ,

$2\left(3\right)+\left(3\right)=6+3=9$ ....3

Consider second expression that is, $3b$ .

Substituting the value of $b=1$ ,

$3\left(1\right)=3$ ....4

Substituting the value of $b=2$ ,

$3\left(2\right)=6$ ....5

Substituting the value of $b=3$ ,

$3\left(3\right)=9$ ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0

3 years ago

koda Buys 0.75 kg of cortos,which ia 5times the mas of the union he also Buys. How much does the union weigh?

kari74 [83]

Answer:

0.15kg

Step-by-step explanation:

Given data

We are told that

0.75 kg of cortos weights 5times the mas of the onion

We want to find the mass of 1 onion

Hence

0.75 kgcortos = 5 onions

x cortos = 1 onions

x= 0.75/5

x= 0.15kg

Hence 1 onion will weigh 0.15kg

4 0

3 years ago