The division equation that has a quotient of 13 is 1/1/13 = 13
<h3>How to determine the equation?</h3>
The given parameters are:
- Quotient = 13
- Dividend = Whole number
- Divisor = Unit fraction i.e. 1/n where n is an integer.
A division equation is represented as:
Dividend/Divisor = Quotient
Substitute 13 for the Quotient
Dividend/Divisor = 13
Recall that:
Unit fraction = 1/n
So, we have:
Dividend/1/n = 13
Let n = 13.
So, we have:
Dividend/1/13 = 13
This gives
13 * Dividend = 13
Divide both sides by 13
Dividend = 1
So, we have:
1/1/13 = 13
Hence, the division equation is 1/1/13 = 13
Read more about division equations at:
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Answer:
The quadratic polynomial with integer coefficients is 
.
Step-by-step explanation:
Statement is incorrectly written. Correct form is described below:
<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em>
<em>. </em>
Let be 
and 
roots of the quadratic function. By Algebra we know that:
(1)
Then, the quadratic polynomial is:
The quadratic polynomial with integer coefficients is .
(3x + 5)° + (10x - 7)° = 180°
13x + (-2) = 180
13x = 180 + 2
13x = 182
x = 14
∠QRT = 3 * 14 + 5 = 42 + 5 = 47°
∠TRS = 10 * 14 - 7 = 140 - 7 = 133°
Givens
Area = 200 square feet
Formula
A = s^2
Soluton
s^2 = 200 square feet.
Take the square root of both sides.
square root s^2 = square root (200)
You should use a calculator to find the square root of 200
√
200
=
is the way to put it into the calculator.
s = 14.1 feet on each side. <<<<< Answer
