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slamgirl [31]
3 years ago
5

Solve for y in this equation

Mathematics
1 answer:
Trava [24]3 years ago
3 0

Answer:

y= -1 1/3

Decimal form: -1.3

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You have to have the same denominator for both fractions, so I would multiply 3/4 by 3 that would give you 9/12 and the other one is 7/12. This means that the final answer would be 9/12>7/12.
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Can anyone tell me the area? I will give brainlist if I'm able to​
pantera1 [17]

Answer:

143 yds^2

Step-by-step explanation:

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What is the area of a circle with a radius of 7 cm? (Use 3.14 for , and round to the nearest tenth.)
jarptica [38.1K]

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5 0
3 years ago
Read 2 more answers
What is the 48th term of the arithmetic sequence with this explicit formula?
mariarad [96]

Option B

48th term of arithmetic sequence is -152

<h3><u>Solution:</u></h3>

Given that a arithmetic sequence has explict formula,

a_n = -11 + (n - 1)(-3)

To find: 48th term of the arithmetic sequence

The nth term of arithmetic sequence can be found by substituting the required value of n in the explict formula

So 48th term of the arithmetic sequence can be found by substituting n = 48 in explict formula

a_n = -11 + (n - 1)(-3)

Plug in n = 48

a_{48} = -11 + (48 - 1)(-3)

On solving we get,

a_{48} = -11 + (47)(-3)\\\\a_{48} = -11 - 141\\\\a_{48} = - 152

Thus 48th term of arithmetic sequence is -152

4 0
3 years ago
. Mr. Donut wants to paint a donut on the wall of his restaurant. The diameter of the outside edge of the donut will be 22 inche
KATRIN_1 [288]

Answer:

The area needed to be painted is approximately 301.44 square inches.

Step-by-step explanation:

The shape of a donut is represented by two concentrical circles, whose area is described by the following formula:

A =A_{g}-A_{s} (Eq. 1)

Where:

A - Total area of the donut, measured in squared inches.

A_{g} - Area of the greater circle, measured in square inches.

A_{l} - Area of the lesser circle, measured in square inches.

By using the definition of the area of the circle, we expand the equation above:

A = \frac{\pi}{4}\cdot D^{2}_{ext} - A_{s} (Eq. 1b)

If we know that \pi = 3.14, D_{ext} = 22\,in and A_{s} = 78.5\,in^{2}, the area needed to be painted is:

A = \frac{(3.14)\cdot (22\,in)^{2}}{4}-78.5\,in^{2}

A \approx 301.44\,in^{2}

The area needed to be painted is approximately 301.44 square inches.

6 0
3 years ago
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