9514 1404 393
Answer:
11
Step-by-step explanation:
4 × (2 3/4) = 4×2 + 4×(3/4) = 8 + 3 = 11
or
4 × (2 3/4) = 4 × 11/4 = 11
Answer:
use pythagorean theorem
Step-by-step explanation:
a^2+b^2=c^2
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
9514 1404 393
Answer:
5.1 cm²
Step-by-step explanation:
The area of a segment is given by the formula ...
A = 1/2r²(α -sin(α)) . . . . . where α is the central angle in radians
For this segment, its area is ...
A = 1/2(6 cm)²(7π/18 -sin(70°)) ≈ 5.077 cm²
The area of the segment is about 5.1 square centimeters.
_____
The angle is converted to radians by multiplying by π/180°. Then a 70° angle is π(70°/180°) = 7π/18 radians.
Answer:
you may
2x+15+4x+21=90 simplified is 6x+36=90
m<a=33º
m<b=90º
m<c=57º
Step-by-step explanation:
6x+36=90
6x=54
x=9
2(9)+15=33
4(9)+21=57
