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3 years ago

12

1.2(4x – 1) = 8x – 2

1 answer:

zysi [14]3 years ago

3 0

6x

Step-by-step explanation:

1.2(4x-1)=8x-2=6x

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Mr. Dunbar takes his wife out to dinner at Macados to celebrate the holidays. Their total bill was $48.36 but he had a coupon to

viktelen [127]

Answer:

$51.38 or $60.45

Step-by-step explanation:

$48.36 minus 15 percent is $41.10. If you're tipping the waitress 25 percent from that price, then it would be $51.38. If you're tipping the waitress 25 percent from the original price, it would be $60.45.

3 0

3 years ago

Use matrix addition to solve this equation

REY [17]

Answer:

c11 = 8
c31 = 20
c22 = 14

Step-by-step explanation:

The sum of two matrices is the sum of corresponding terms.

$\left[\begin{array}{ccc}3&1&0\\-1&2&4\\9&7&-2\end{array}\right] +\left[\begin{array}{ccc}5&2&4\\1&12&3\\11&3&-2\end{array}\right] =\left[\begin{array}{ccc}8&3&4\\0&14&7\\20&10&-4\end{array}\right]$

8 0

3 years ago

Read 2 more answers

I need some... help anyone have a clue?

IrinaVladis [17]

Answer:

(x+3)(x+5)

Step-by-step explanation:

8 0

2 years ago

Solve for x 5x + 4/2 = 7

aev [14]

Answer:

x=2

Step-by-step explanation:

5x+ $\frac{4}{2}$ = 7

5x+4 =7 (2)

5x+4=14

5x=14-4

5x=10

$\frac{5x}{5}$ = $\frac{10}{5}$

x=2

8 0

3 years ago

Read 2 more answers

The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

8 0

3 years ago