All categories

2 years ago

Please help me with my maths i am suffering may god bless you!,,,

Mathematics

2 answers:

jolli1 [7]2 years ago

6 0

Answer:

a= 5

b=7

c=0

Step-by-step explanation:

i cant explain it but here yu go

Ainat [17]2 years ago

5 0

Answer:

a is 5. B is 7 and c is 0

Step-by-step explanation:

6+5+2 =13

add the 1 to the next row.

1+3+9+4=17

add the 1 to the next row.

1+1+3+0=5

You might be interested in

Plz help me well mark brainliest!!

gregori [183]

Answer:

x=-52

1/3x-2/3=-18

multiply both sides by 3

x-2=-54

x=-54+2

x=-52

4 0

3 years ago

Read 2 more answers

Please help with this

gtnhenbr [62]

Answer:

the correct answer A. <1 and <7 , <2 and <8

5 0

3 years ago

t When you reverse the digitals in a certain number you increase its value by 27. Find the number if the sum fixes digits is 9.

TiliK225 [7]

The number=10x+y
we suggest this system of equations:
(10y+x)-(10x+y)=27
x+y=9 ⇒x=9-y

Can solve this system of equations by susbstitution method.
(10y+(9-y)-(10(9-y)+y)=27
10y+9-y-(90-10y+y)=27
10y-y+10y-y=27-9+90
18y=108
y=108/18
y=6

x=9-y
x=9-6
x=3

The number=10x+y=10(3)+6=36

Answer: the number is 36.

to check:
63-36=27
6+3=9

3 0

4 years ago

Which is the graph of y = 1/x?

irina1246 [14]

<u>answer:</u> the first graph

<u>explanation:</u>

it would not be the second one because it is a slope (y = mx + b) and so would be the third choice.

i don't think it would be the last one because it's going only up to 40. which the equation say only y = 1/x and it's not a big number equation.

hope this helps! ❤ from peachimin

i attached this image which is sorta similar to the the to this equation:

6 0

3 years ago

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago