To represent the solution set of a linear equation parametrically, we introduce other parameters like s and t for the free variables.
Every linear equation has n - 1 free variables where n is the number of variables.
For x + y + z = 2, we have 3 variables and 3 - 1 = 2 free variables.
First, let y and z be the free variables, we first solve the linear equation for x to get:
x = 2 - y - z
Therefore , the parametric representation of the solution set is given by :
x = 2 - s -t
y = s
z = t
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A because the 6 and 3 cancel out
Then 2 x 8 is (16) and 15 x 5 is (75)
Making it A
You can write any decimal as a precent by moving the decimal 2 places to the right so
0.51 = 51%
5.1% < 51%
5.1% < 0.51
or, any precent can be written as a decimal by moving the decimal points two point to the left so
5.1% = 0.051
0.051 < 0.51
5.1% < 0.51
You have to make a proportion:
12+x/8=8/x
Then cross multiply to solve for x
Answer:
P(A|D) and P(D|A) from the table above are not equal because P(A|D) = and P(D|A) =
Step-by-step explanation:
Conditional probability is the probability of one event occurring with some relationship to one or more other events
.
P(A|D) is called the "Conditional Probability" of A given D
P(D|A) is called the "Conditional Probability" of D given A
The formula for conditional probability of P(A|D) = P(D∩A)/P(D)
The formula for conditional probability of P(D|A) = P(A∩D)/P(A)
The table
↓ ↓ ↓
: C : D : Total
→ A : 6 : 2 : 8
→ B : 1 : 8 : 9
→Total : 7 : 10 : 17
∵ P(A|D) = P(D∩A)/P(D)
∵ P(D∩A) = 2 ⇒ the common of D and A
- P(D) means total of column D
∵ P(D) = 10
∴ P(A|D) =
∵ P(D|A) = P(A∩D)/P(A)
∵ P(A∩D) = 2 ⇒ the common of A and D
- P(A) means total of row A
∵ P(A) = 8
∴ P(D|A) =
∵ P(A|D) =
∵ P(D|A) =
∵ ≠
∴ P(A|D) and P(D|A) from the table above are not equal
Step-by-step explanation:
