Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
The Solution:
From the graph, there is a point of intersection between the graphs of the two equations in the system. This implies that:
There is a viable solution to the given system of equations at the point where the two lines intersect, that is, at the point (26,34).
So, the correct answer is [option 3]
Answer: A
Step-by-step explanation: Hope this help :D
1) false
2)true
3)-1.346
<span>4)<span><span>x=−5</span><span>x=-5</span></span></span>
<span>5)<span>x=3</span></span>
<span>6)x =~ 3.91 </span>
<span>7) x = 162.69 </span>
<span>hope I helped :)</span>
7)
