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3 years ago

A marching band sold 350 tins of popcorn for $8 each. Each tin cost the

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

Answer:

The band made $1,400

Step-by-step explanation:

8-4=4

350*4=1,400

LuckyWell [14K]3 years ago

3 0

The answer is 1,400$

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Calculate the area of triangle ABC given A(1, 1), B(7, 1), and C(4, 6).

s344n2d4d5 [400]

Answer:

Area=15

Step-by-step explanation:

Area=bh1/2

6*5=30

30*1/2

4 0

3 years ago

Two baseball players hit 43 home runs combined last season. The first player hit 1 1 more home runs than twice the number of hom

aksik [14]

1st player hit 11 home runs and the 2nd player hit 32 home runs.

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3 years ago

Read 2 more answers

John withdraws $40.00 from her savings account each month. What integer represents the net effect on her balance after 5 months?

lina2011 [118]

Answer:

The net effect of amount in John account after 5 months is $A - $200

Step-by-step explanation:

Given as :

The amount of money withdraws by John each month from his account = $40

Let The total amount of money did John had in his account = $A

Let the amount left in John account after 5 months of withdraw = $x

<u>So, According to question</u>

∵ Each month the money withdraw from account = $40

∴ In 5 months , the money withdraw = $40 × 5

I.e In 5 months , the money withdraw = $200

So, The left money in account after withdraw in 5 months = $A - The amount withdraw in 5 months

I.e x = $A - $200

So, The balance in account after 5 months = x = $A - $200

Hence, The net effect of amount in John account after 5 months is $A - $200 Answer

6 0

3 years ago

Newton's Law of Cooling states that the rate of change of the temperature of an object, T, is proportional to the difference of

maria [59]

Answer:

305 °F

Step-by-step explanation:

The core temperature of the object after 4 hours can be found using an exponential decay formula to model the decay of the difference between core temperature and ambient.

<h3>Cooling Model</h3>

The solution to the differential equation described by Newton's law of cooling is the exponential equation ...

y = ab^t +c

where 'a' is the initial core temperature difference from ambient, 'b' is the decay factor of that difference in 1 unit of time period t. 'c' is the ambient temperature.

For this problem, the ambient temperature is c=80, and the differences of interest are ...

a = 1200 -80 = 1120

b = (830 -80)/1120 = 75/112

Using these values in the model gives ...

y = 1120(75/112)^t +80 . . . . . . where y(t) is the core temperature at time t

Note that units of time are hours.

<h3>Application</h3>

We want y when t=4.

y = 1120(75/112)^4 +80 ≈ 1120(0.20108) +80 ≈ 305.212

The core temperature after 4 hours is about 305 °F.

<em>Additional comment</em>

The differential equation will have a solution of the form ...

$T-T_R=(T_0-T_R)e^{kt}$

where k = ln(75/112) ≈ -0.40101

In the above, we defined b = e^k = 75/112. Accuracy with this fraction can be better than using a truncated value of k.

5 0

2 years ago

Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>

3 0

3 years ago