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3 years ago

This is very hard for me lol

Mathematics

1 answer:

Alika [10]3 years ago

7 0

Answer:

Step-by-step explanation:

If you think about it very carefully, the triangles and rectangles will fold up to become figure C.

Hope this helps!

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The prices of consumer goods do not always exactly follow the CPI. The following chart shows several consumer items, along with

zloy xaker [14]

The reasonable estimate of the current customer price index is 195. The option B is the correct option.

<h3>Customer price index</h3>

Customer price index is the price index which measures the weight average of price of basket of customers goods or services.

It can be given as,

$\rm CPI_t=\dfrac{C_t}{C_0}\times 100$

Here $\rm C_t$ is the cost of market basket in current period and $\rm C_0$ is the cost of market basket in the base period.

Cost of market basket in current period is

$\rm C_t=15.66+119.75+23.99+37.50\\\\C_t=196.9$

Cost of market basket in 1983 is,

$\rm C_0=8.85+71.25+13.95+22.7\\\\C_0=116.8$

Substitute all the values in the formula

$\rm CPI_t=\dfrac{C_t}{C_0}\times 100\\\\\rm CPI_t=\dfrac{196.9}{116.8}\times 100\\\\\rm CPI_t=1.685\times 100 \\\\ CPI_t=168.5\\\\\rm CPI_t= 170 \ \rm approx$

Thus the value of current CPI is 168.5 which is near about the 170.

Hence, the reasonable estimate of the current customer price index is 195. The option B is the correct option.

Learn more about the customer price index here;

brainly.com/question/25495502

3 0

2 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

3 years ago

Read 2 more answers

Speed = distance divided by time taken. car 1 travels 10 miles every 5 minutes. car 2 travels 30 miles every 20 minutes. what is

Setler [38]

Car 1
2 miles............................1 minute
10 miles.........................5 minutes
20 miles.........................10 minutes
40 miles..........................20 minutes
car2
1.5 miles...........................1 minute
15miles.............................10 minutes
30 miles...........................20 minutes
the difference is 0.5 miles per minute

0.5*60=30 miles/hour

5 0

3 years ago

11 nickels to 11 dimes are what ratio?

castortr0y [4]

Answer: 11:11

Step-by-step explanation:

The ratio is 11 nickles to 11 dimes, Take away the names of the coins and there is your answer. (If i'm correct)

7 0

3 years ago

Read 2 more answers

The list below shows the Highlight in inches of the player on a man college basketball team

boyakko [2]

We have the data set:

{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}

This data set has 10 items.

To complete the data summary is helpful to sort the data:

{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}

The minimum value is 72.

<em>The quartile divides the data set in 4 parts. </em>

<em>The first quartile is the value for which 25% of the data is below.</em>

<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>

<em>The third quartile is the value for which 75% of the data is below.</em>

In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.

The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.

This values are 73 (2nd position) and 77 (3rd position), so the average is:

$Q_1=\frac{73+77}{2}=75$

We can repeat this with the other quartiles:

$\begin{gathered} Q_2=M=\frac{79+79}{2}=79 \\ Q_3=\frac{82+82}{2}=82 \end{gathered}$

Then:

The first quartile is 75.

The median (second quartile) is 79.

The third quartile is 82.

The maximum value is 83.

7 0

1 year ago

This is very hard for me lol​

This is very hard for me lol