Answer:
a) 0.4164
Step-by-step explanation:
Mean lifespan (μ) = 18.8 days
Standard deviation (σ) = 2 days
For any given lifespan 'X', the z-score is:

For X=12.04 days:

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.
For X=18.38 days:

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.
The probability that a butterfly lives between 12.04 and 18.38 days is

Answer:
9.1 x 10² = 910
9.1 / 10² = 0.091
Step-by-step explanation:
The answer is 62 B can u plz mark brainliest
Answer:
The estimate is 
Step-by-step explanation:
From the question we are told that
The sample size is n = 522
The sample proportion of students would like to talk about school is 
Given that the confidence level is 90 % then the level of significance can be mathematically evaluated as



Next we obtain the critical value of
from the normal distribution table, the value is

Generally the margin of error can be mathematically represented as

=> 
=> 
Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is

substituting values

Final Answer: No Solution
Steps/Reasons/Explanation:
Question: 
<u>Step 1</u>: Divide both sides by
.

<u>Step 2</u>: Expand.

<u>Step 3</u>: Since
is false, we have no solution.
No Solution
~I hope I helped you :)~