Which value for the constant d makes x=-1 an extraneous solution in the following equation? square 8-x = 2x + d. PLEASE
2 answers:
Answer:
Step-by-step explanation:
substitute x=-1 into the eqn
sqrt (8-(-1)) = 2(-1)+d
sqrt(9) = -2+d
d = 2+sqrt(9)
as 3^2 = 9 and (-3)^2 = 9
sqrt(9) = -3 is an extraneous solution
so d = 2+(-3) = -1
Answer:
Step-by-step explanation:
An extraneous solution occurs when a square root is taken which generates a +ve and -ve solution.
In this case, squareroot (8-(-1)) = squareroot (9) = +3 and -3
The extraneous solution is -3 = 2(-1) + d
d = -3 + 2 = -1
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