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3 years ago

Which value for the constant d makes x=-1 an extraneous solution in the following equation? square 8-x = 2x + d. PLEASE

Mathematics

2 answers:

makkiz [27]3 years ago

7 0

Answer:

Step-by-step explanation:

substitute x=-1 into the eqn

sqrt (8-(-1)) = 2(-1)+d

sqrt(9) = -2+d

d = 2+sqrt(9)

as 3^2 = 9 and (-3)^2 = 9

sqrt(9) = -3 is an extraneous solution

so d = 2+(-3) = -1

zimovet [89]3 years ago

6 0

Answer:

Step-by-step explanation:

An extraneous solution occurs when a square root is taken which generates a +ve and -ve solution.

In this case, squareroot (8-(-1)) = squareroot (9) = +3 and -3

The extraneous solution is -3 = 2(-1) + d

d = -3 + 2 = -1

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