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Alexxx [7]

Answer:

The y intercept is 80 and the line of the best fit is -3/5

Step-by-step explanation:

5 0

3 years ago

At a party of 102 people,17 lb of potato salad is served. a. Write and solve an equation to find how many people each pound of p

Novay_Z [31]

Each pound of potato salad serves 6 people and the average number of pounds of potato salad that each person is served will be $\frac{1}{6}$ pound.

Explanation

At a party of 102 people, 17 pounds of potato salad is served.

a. Suppose, each pound of potato salad is served to $x$ number of people.

So, 17 pounds of salad is served to $(17*x)$ or $17x$ number of people. That means......

$17x= 102\\ \\ x= \frac{102}{17}=6$

So, each pound of potato salad is served to 6 people.

b. Suppose, the average number of pounds of potato salad that each person is served is $y$

So, the total number of pounds of salad, served to 102 people $= (y*102)$ pounds $=102y$ pounds. That means .....

$102y= 17\\ \\ y= \frac{17}{102}= \frac{1}{6}$

So, the average number of pounds of potato salad that each person is served will be $\frac{1}{6}$ pound.

3 0

3 years ago

There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3

jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0

3 years ago

Answer fast for pts

sdas [7]

Answer:

Since she arrived at 8:30 its not accurate because her records started at the time she arrived so she didnt get the times of the students that arrived before her

Step-by-step explanation:

Hope this helps:))

4 0

3 years ago

Read 2 more answers

Eric randomly surveyed 150 adults from a certain city and asked which team in a contest they were rooting for, either North Hig

Romashka-Z-Leto [24]

Answer:

B

Step-by-step explanation:

A 95% confidence level interval will have 0.52 (lower interval) & 0.68 (upper interval) which means that that if 90 individuals root for North HS then p value is 0.6 which will fall in the 95% confidence interval range.
For the option B the p value will also be same as in case A hence B is true as an alternative hypothesis.
We can calculate P value

Confidence Interval = p ± z $\sqrt{p(1-p)/n}$

4 0

3 years ago