Answer:
7 cars per row
Step-by-step explanation:
Answer:
No, he cannot
Step-by-step explanation:
Lets say the student takes the maximum socre on his last test, so he gets 100. Now, his average on the six texts will be:
(75+85+90+95+94+100)/6 = 89.83
So, if taking 100 is not enough to get to the average of 90, this means he would need a score greater than 100, which is impossible as 100 is the maximum. So, the student CAN'T get an A
(-1,3) (0,6) (1,9) (2,12) and (3,15)
The pattern is up 1 over 3
Answer:
B=25
Step-by-step explanation:
b=2(10)^2(10-5)/10(10
b=2(100)(5)/100
b=(200)(5)/100
B=2500/100
B=25
6(x + 5)² - 5(x + 5)
6(x + 5)(x + 5) - 5(x) - 5(5)
6(x(x + 5) + 5(x + 5)) - 5x - 25 Distributive Property
6(x(x) + x(5) + 5(x) + 5(5)) - 5x - 25
6(x² + 5x + 5x + 25) - 5x - 25 FOIL
6(x² + 10x + 25) - 5x - 25
6(x²) + 6(10x) + 6(25) - 5x - 25
6x² + 60x + 150 - 5x - 25 Distributive Property
6x² + 60x - 5x + 150 - 25
6x² + 55x + 125 Adding Equations
6x² + 30x - 25x - 125
6x(x) + 6x(5) + 25(x) + 25(5)
6x(x + 5) + 25(x + 5)
(6x + 25)(x + 5) Factoring
