1 year ago

20/5 as a whole number

Mathematics

1 answer:

taurus [48]1 year ago

8 0

Answer:

4 is the answer

Step-by-step explanation:

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The bulbs on the bay holiday drive through attraction charges 12 dollars per car plus 1 dollar for every individual,(p), in the

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This problem mentions 'CHOICE,' which means you need to share the several possible answers that came with this problem.

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2 years ago

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dolphi86 [110]

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Jerri was using a recipe for a large cake that required one-fourth of a tablespoon of cinnamon. Instead of making one large cake

Sergeeva-Olga [200]

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2 years ago

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Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA

liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

$\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

We take left hand side of the given equation and solve it,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}$

Since, abc = 1,

$\frac{1}{c}=ab$ and c = $\frac{1}{ab}$

By substituting these values in the expression,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}$

$=\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}$

$=\frac{1+b+ab}{1+b+ab}$

$=1$

Which equal to the right hand side of the equation.

Hence, $\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

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2 years ago