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Sladkaya [172]
3 years ago
7

Pls help!! n33d help

Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

6 and 12

Explanation:

(b.) is under set A but not set B, meaning that all the elements there are multiples of 3 that are not odd numbers.

all the multiples of 3 that are less than 16: 3 6 9 12 15

all the multiples of 3 that are even numbers: <u>6 12</u>

thus, the elements that go in (b.) are 6 and 12.

i hope this helps! :D

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tensa zangetsu [6.8K]

Answer:

Hannah

Step-by-step explanation:

She spent more time on the interviews thus got to less

8 0
3 years ago
Read 2 more answers
Find the greatest common factor of numbers using prime factorization 32 and 90
Gemiola [76]

the greatest common factor of 32 and 90 is 2

8 0
3 years ago
Find the equation of the line<br><br> Y= __x + __
djyliett [7]

Answer:

y=2x+5

Step-by-step explanation:

0,5

0,7

7-5 is 2

2/0 is 2

to check answer:

(2*0)+5

0+5

=5

8 0
3 years ago
Read 2 more answers
a video game arcade offers a yearly membership with reduced rates for game play. A single membership costs $60 per year. Game to
7nadin3 [17]

slope is $0.10            <em>($1.00 per 10 tokens = $0.10)</em>

y-intercept is $60    <em>($60 is the annual fee)</em>

y = .10x + 60            <em>(y = mx + b)</em>  

domain is x ≥ 0        <em>(you can't buy a negative number of token)</em>

range is y ≥ 60        <em>(input the domain (x ≥ 0) to find the range)</em>

Answer: the y-intercept of the function is $60

6 0
3 years ago
Read 2 more answers
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
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