Answer:
A patient safety event
Explanation:
A patient safety event is an event, incident, or condition that could have resulted or did result in harm to a patient.
Reduce the I.V. flow rate and hang the recommended treatment intervention would be the most effective way to improve the nursing practice.
What should the nurse do?
The nurse should keep the I.V. access open and start the correct solution when a client is receiving the incorrect solution. The catheter does not need to be taken out by the nurse. The client would experience pointless needle sticks if this were done. Waiting until the next bottle is scheduled to be delivered is improper and puts both the client and the nurse in legal danger. The nurse should write out an incident report describing the precise problem after beginning the correct solution.
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Answer:
10.6 % .
Explanation:
From the question above we can get the following parameters which we are going to use to solve the problem; mass of the solvent, which in this case is water= 55.0 grams and the mass of the SOLUTE which is the vitamin C, C6H8O6 in this problem = 6.50 grams.
Calculating the percent weight we are to divide the mass of the solute by the mass of the solution and multiply it by 100. This can be represented mathematically by using the equation below.
Percent weight= (mass of solute/ mass of solution) × 100.
Note that the mass of the solution is equal to the (mass of solute + mass of solvent) = 6.5 grams + 55.0 grams = 61.5 grams.
Hence, percent weight =( 6.5 grams/ 61.5 grams) × 100.
Percent weight = 0.10569105691 × 100 = 10.5691056911.
Percent weight = 10.6 %.
Answer: 30 meq
Explanation:
We know that 1 gallon = <u>3.785 Litres</u>
1 litre = <u>1000 milliliters</u>
1 gallon = <u>3785 ml</u>
<u>Concentration = weight/volume </u>
= 565/3785
= 0.149 g/ml
= 149 mg/ml
Multiplying with 15 ml we get
= 149*15 = <u>2235 mg</u>
<u>The atomic weights of:</u>
Potassium (K) = 39
Chlorine (Cl) = 35.5
Finding the equivalent weight of Kcl = 39 + 35.5 = 74.5
So, 1 equivalent of KCl is 74.5 g
= 2235 mg * 1 meq/74.5 mg = 30 meq K+
Therefore, there are 30 milliequivalents of K in 15 ml of this solution
Tdap, HPV, MCV, varicella, and influenza (if during influenza season).
