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NARA [144]
2 years ago
6

1 gal of KCL solution by mixing 565 g of KCL in an appropriate vehicle. How many milliequivalents of K are in 15 ml of this solu

tion
Medicine
1 answer:
Ira Lisetskai [31]2 years ago
3 0

Answer: 30 meq

Explanation:

We know that 1 gallon = <u>3.785 Litres</u>

1 litre = <u>1000 milliliters</u>

1 gallon = <u>3785 ml</u>

<u>Concentration = weight/volume </u>

= 565/3785

= 0.149 g/ml

= 149 mg/ml

Multiplying with 15 ml we get

= 149*15 = <u>2235 mg</u>

<u>The atomic weights of:</u>

Potassium (K) = 39

Chlorine (Cl) = 35.5

Finding the equivalent weight of Kcl = 39 + 35.5 = 74.5

So, 1 equivalent of KCl is 74.5 g

= 2235 mg * 1 meq/74.5 mg = 30 meq K+

Therefore, there are 30 milliequivalents of K in 15 ml of this solution

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