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Wittaler [7]
3 years ago
8

What is the maximum number of​ x-intercepts that a polynomial of degree 7 can​ have

Mathematics
1 answer:
Daniel [21]3 years ago
5 0
Polynomial of degree seven can have the maximum 7 real solutions,
so maximum number of x-intercepts is also 7.
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HELPP!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step.  The equation is

8-3\sqrt[5]{x^3}=-7

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time.  First thing is to subtract 8 from both sides:

-3\sqrt[5]{x^3}=-15

The goal is to isolate the term with the x in it, so that means that the -3 has to go.  Divide it away on both sides:

\sqrt[5]{x^3}=5

Let's rewrite that radical into exponential form:

x^{\frac{3}{5}}=5

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely.  On the right, let's rewrite that back in radical form to solve it easier:

x=\sqrt[3]{5^5}

Let's group that radicad into groups of 3's now to make the simplifying easier:

x=\sqrt[3]{5^3*5^2} because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

x=5\sqrt[3]{5^2} which is the same as:

x=5\sqrt[3]{25}

8 0
3 years ago
PLEASE HELP ME !! PLEASE !!
Yakvenalex [24]
I think that it is a ok
6 0
3 years ago
A quality control inspector has drawn a sample of 19 light bulbs from a recent production lot. If the number of defective bulbs
Inessa05 [86]

Answer:

0.0016283

Step-by-step explanation:

Given that:

Proportion of defective bulbs, p = 30% = 0.3

Sample size, n = 19 bulbs

Probability that the lot will pass inspection :

P(none of the 19 is defective) Or P(only one of the 19 is defective)

P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19

0.7^19 = 0.0011398

P(only one of the 19 is defective) :

P(1 defective) * P(18 not defective )

(0.3) * (1 - 0.3)^18

0.3 * 0.7^18

0.3 * 0.001628413597910449 = 0.0004885

Hence,

P(none of the 19 is defective) + P(only one of the 19 is defective)

0.0011398 + 0.0004885) = 0.0016283

8 0
3 years ago
What is the sum of 5x^2y and (2xy^2 + x^2y)
eimsori [14]
Recognize that you must combine "like" terms.  5x^2y and x^2y are "like" terms.

Adding them together, you get 6x^2y.  

Now add 2xy^2 to 6x^2y.  These are NOT "like" terms, so you end up with 
6x^2y+2xy^2 as your final answer.  This answer is acceptable as is.  

However, you could factor out the common factors:  2xy(3x+y).
8 0
3 years ago
Find the values of the variables
Nikolay [14]

Answer:

corresponding value of equal matrix is equal

a=10

b= -6

c=3

Step-by-step explanation:

4 0
3 years ago
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