Question

Q bisects PR. If PR=28, and PQ = 2x+5, what is the value of x?

Answer 1

Answer:

$x = 4.5$

Step-by-step explanation:

Given

$PR = 28$

$PQ = 2x + 5$

Required

Find x

Since Q is a bisector of PR; This mean PR is divided into exactly two equal parts;

Hence:

$PR = 2 * PQ$

Substitute values for PR and PQ

$28 = 2 * (2x + 5)$

Divide both sides by 2

$\frac{1}{2} * 28 =\frac{1}{2} * 2 * (2x + 5)$

$14 = 2x + 5$

Solve for 2x

$2x = 14 - 5$

$2x = 9$

Solve for x

$x = \frac{9}{2}$

$x = 4.5$