We are tasked to solved for the length of the ramp having an inclination of 15 degrees with the ground and 10 feet from the end of the ramp to the base of the building of the ground. Using trigonometric properties, we have a formula given an angle and the its opposite sides which is,
sin(Angle)=opposite/hypothenuse
hypothenuse would be the distance or the length of the ramp.
so we have,
sin(15)=10/hypothenuse
Cross-multiply, we have,
hypothenuse=10/sin(15)
using scientific calculator having a DEG mode,
hypothenuse=38.63703
Rounding of in nearest tenth we get,
hypothenuse=38.6 ft
Therefore, the ramp is 38.6 ft long
"300 K and 2 atm" is the condition among the conditions given in the question that you can <span>expect helium gas to deviate most from ideal behavior. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has helped you.</span>
<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>
<em><u>Solution:</u></em>
<em><u>The volume of triangular prism is given as:</u></em>
Given that,
A triangular prism container is full of water of 428 cubic cm
The water is 10 cm deep
Therefore,
v = 428 cubic cm
h = 10 cm
<em><u>Substituting the values we get,</u></em>
Thus the base area of triangular prism container is 42.8 cubic centimeter
PEMDAS- Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction.
