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Ksenya-84 [330]
3 years ago
12

Compute r6r6, l6l6, and m3m3 to estimate the distance traveled over [0, 3] if the velocity at half-second intervals is as follow

s:
Mathematics
1 answer:
trapecia [35]3 years ago
3 0

For R6 and L6, t= (3- 0) / 6= 0.5. For M3, t= (3- 0)/ 3 = 1. Then

For R6 we will add all the velocity given from 12 to 20 and then multiply it by 0.5 seconds

R6 = 0.5 s ( 12 + 18 + 25 + 20 + 14 + 20 ) m/ sec = 0.5 (109) m = 54.5 m,

For L6 we will add all the velocity given from 0 to 14 and then multiply it by 00.5 as well.

L6 = 0.5 sec ( 0 + 12 + 18 + 25 + 20 + 14 ) m/ sec = 0.5 (89 ) m = 44.5 m.

For M3:

M3 = 1 sec (12 + 25 + 14) m/ sec = 51 m.

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10*15= 150

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Step-by-step explanation:

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Express the following as:<br>ax+by+c=0<br><br>-2x+3y=6​
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The expression -22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

<h3>Linear Equations</h3>

The given equation is:

-2x + 3y = 6

Comparing the equation above with ax + by + c = 0

Rewrite -2x + 3y = 6 in the form ax + by + c = 0

-2x + 3y - 6 = 0

If -2x + 3y - 6 = 0 is compared with ax + by + c = 0

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Therefore, the expression-22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

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8 0
2 years ago
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Can someone please help me?
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Answer:

The answer is 27

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The reason being, you can solve this 2 ways.

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