Answer: Associative property
Step-by-step explanation:
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Assuming -5 is m
y-3 = -5 (x + 7)
y - 3 = -5x - 35
y = -5x - 33
hope this helps , give brainliest.
The x-intercept is present where y = 0
2x + 5y - 10 = 0
2x - 10 = -5y
2x - 10 = -5(0)
2x = 10
x = 5
The y-intercept is present where x = 0
2x + 5y = 10
2x + 5y - 10 = 0
5y - 10 = -2(0)
5y = 10
y = 2
Answer:
b1 = 2 ; r = 3
Step-by-step explanation:
Given that :
if b3 −b1 = 16 and b5 −b3 = 144.
For a geometric series :
Ist term = a
Second term = ar
3rd term = ar^2
4th term = ar^3
5th term = ar^4 ;...
If b3 - b1 = 16;
ar^2 - a = 16
a(r^2 - 1) = 16 - - - (1)
b5 - b3 = 144
ar^4 - ar^2 = 144
ar^2(r^2 - 1) = 144 - - - - (2)
Divide (1) by (2)
a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144
a / ar^2 = 1 / 9
ar^2 = 9a
Substitute for a in ar^2 - a = 16
9a - a = 16
8a = 16
a = 2
From ar^2 - a = 16
2r^2 - 2 = 16
2r^2 = 16 + 2
2r^2 = 18
r^2 = 18 / 2
r^2 = 9
r = √9
r = 3
Hence ;
a = b1 = 2 ; r = 3
