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2 years ago

Expand the following algebraic expression (n + 5) (n + 3)

Mathematics

2 answers:

marshall27 [118]2 years ago

6 0

${n}^{2} + 30n + 15$

Mamont248 [21]2 years ago

5 0

Answer:

n²+8n+15

Step-by-step explanation:

Given expression is (n+5)(n+3).

We have to expand it.

(n+5)(n+3)

Each of the two terms in first binomial is multiplied by the second binomial.

n(n+3)+5(n+3)

Each of the two terms in first binomial is multiplied by the each term of second binomial.

n(n)+n(3)+5(n)+5(3)

simplify

n²+3n+5n+15

add like terms

n²+n(3+5)+15

n²+n(8)+15

n²+8n+15 which is the answer.

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An absolute value graph is an example of a non-linear graph. True or False?

nirvana33 [79]

The answer is true. Your welcome

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2 years ago

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This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the perc

Ahat [919]

The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

<h3><u>Solution:</u></h3>

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

<em><u>The percent increase is given as:</u></em>

$\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100$

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,

$\begin{aligned}&\text { percentage increase }=\frac{1272-1200}{1200} \times 100\\\\&\text { percentage increase }=\frac{72}{1200} \times 100=6\end{aligned}$

Thus percent increase is 6 %

4 0

2 years ago

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

algol [13]

5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$