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3 years ago

Find the values of x and y

Mathematics

1 answer:

const2013 [10]3 years ago

7 0

Answer:

x = 79 y = 22

Step-by-step explanation:

x would be the same as the other side so 79 * 2 would be 158. A whole triangle is 180. 180 - 158 = 22

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What are the values of x and y? (9x - 19y) (5x - 17) (3x + 3)º X = y =

TEA [102]

Answer: x = 10 and y = 3

Step-by-step explanation:

Due to the x rule, (5x - 17) = (3x + 3)

If we add 17 to both sides:

5x = 3x + 20

Take away 3x from both sides

2x = 20

Divide by 2:

X = 10

This means that (5x - 17) = (3x + 3) = 33

Since all angles must add to 360, the top angle = (360- (33*2)) /2

(360-66) /2

294 /2

147

This shows that 9x - 19y = 147

90 - 19y = 147

Minus 90 both sides

19y = 57

Y = 3

So, x = 10 and y = 3

6 0

2 years ago

Solve a quadratic equation using the zero product property

aksik [14]

Answer:idk

Step-by-step explanation: snnd

6 0

3 years ago

Use the equation of the circle centered at the origin and

Serggg [28]

Answer:

Step-by-step explanation:

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

If we are given x and y as 0 and 5 respectively, and we are also told that the center is (0, 0), our h and k are both 0. Filling in x, y, h, and k we can find the radius. So let's do that:

$(0-0)^2+(5-0)^2=r^2$ and

$0^2+5^2=r^2$ so

$r^2=25$ Our circle's equation is

$x^2+y^2=25$

Since the point in question, (4, 4), lies in the first quadrant, we will concentrate on that quadrant only. To fall within the circle, we can set up an inequality and test the point (4, 4). If it lies ON the circle then the equality would be true. Let's try that first:

$4^2+4^2=25$

Obviously, 16 + 16 does not equal 25, so that point (4, 4) does not lie ON the circle. In fact from that statement alone, we can determine that the point lies outside the circle because

$4^2+4^2>25$

If the inequality < were true then the point would lie inside.

5 0

3 years ago

SHOW YOUR WORK!!!!: -40+2n=4n-8(n+8)

Murljashka [212]

-40 +2n= 4n -8(n+8)

-40 +2n= 4n -8n -64
-40 + 2n = -4n -64
2n = -4n -64 +40
2n=-4n-24
2n+4n=-24
8n=-24
N= -3

Answer is n equals -3

8 0

3 years ago

Read 2 more answers

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago