How many cubic millimeters are present in 0.0923 m3?

Write an SQL statement to display for every restaurant the name of the restaurant (where the name of the restaurant consists of

Rainbow [258]

Using the knowledge in computational language in SQL it is possible to write the code that display for every restaurant the name of the restaurant and for every category of menu item its description.

<h3>Writting the code:</h3>

INSERT INTO Dish Values(13, 'Spring Rolls', 'ap');

INSERT INTO Dish Values(15, 'Pad Thai', 'en');

INSERT INTO Dish Values(16, 'Pot Stickers', 'ap');

INSERT INTO Dish Values(22, 'Masaman Curry', 'en');

INSERT INTO Dish Values(10, 'Custard', 'ds');

INSERT INTO Dish Values(12, 'Garlic Bread', 'ap');

INSERT INTO Dish Values(44, 'Salad', 'ap');

INSERT INTO Dish Values(07, 'Cheese Pizza', 'en');

INSERT INTO Dish Values(19, 'Pepperoni Pizza', 'en');

INSERT INTO Dish Values(77, 'Veggie Supreme Pizza', 'en');

INSERT INTO MenuItem Values(0, 0, 13, 8.00);

INSERT INTO MenuItem Values(1, 0, 16, 9.00);

INSERT INTO MenuItem Values(2, 0, 44, 10.00);

INSERT INTO MenuItem Values(3, 0, 15, 19.00);

INSERT INTO MenuItem Values(4, 0, 22, 19.00);

INSERT INTO MenuItem Values(5, 3, 44, 6.25);

INSERT INTO MenuItem Values(6, 3, 12, 5.50);

INSERT INTO MenuItem Values(7, 3, 07, 12.50);

INSERT INTO MenuItem Values(8, 3, 19, 13.50);

INSERT INTO MenuItem Values(9, 5, 13, 6.00);

INSERT INTO MenuItem Values(10, 5, 15, 15.00);

INSERT INTO MenuItem Values(11, 5, 22, 14.00);

See more about SQL atbrainly.com/question/13068613

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4 0

1 year ago

Extend to also calculate and output the number of 1 gallon cans needed to paint the wal. Hint: Use a math function to round up t

Crank

Answer:

Here is the Python program:

import math #import math to use mathematical functions

height = float(input("Enter wall height (feet): ")) #prompts user to enter wall height and store it in float type variable height

width = float(input("Enter wall width (feet): ")) #prompts user to enter wall width and store it in float type variable width

area = height *width #computes wall area

print('Wall area: {} square feet'.format(round(area))) #displays wall area using round method that returns a floating-point number rounded

sqftPerGallon = 350 #sets sqftPerGallon to 350

paintNeeded = area/ sqftPerGallon #computes needed paint

print("Paint needed: {:.2f} gallons".format(paintNeeded)) #displays computed paint needed up to 2 decimal places

cansNeeded = int(math.ceil(paintNeeded)) #computes needed cans rounding the paintNeeded up to nearest integer using math.ceil

print("Cans needed: {} can(s)".format(cansNeeded)) #displays computed cans needed

colorCostDict = {'red': 35, 'blue': 25, 'green': 23} #creates a dictionary of colors with colors as key and cost as values

color = input("Choose a color to paint the wall: ") #prompts user to enter a color

if color in colorCostDict: #if the chosen color is present in the dictionary

colorCost = colorCostDict.get(color) #then get the color cost from dictionary and stores it into colorCost using get method that returns the value(cost) of the item with the specified key(color)

cost = cansNeeded * colorCost #computes the cost of purchasing paint of specified color per cansNeeded

print("Cost of purchasing {} paint: ${}".format(color,colorCostDict[color])) #displays the real cost of the chosen color paint

print("Cost of purchasing {} paint per {} gallon can(s): ${}".format(color,cansNeeded, cost)) #displays the cost of chosen color paint per cans needed.

Explanation:

The program first prompts the user to enter height and width. Lets say user enter 20 as height and 50 as width so the program becomes:

Wall area computed as:

area = height *width

area = 20 * 50

area = 1000

Hence the output of this part is:

Wall area: 1000 square feet Next program computes paint needed as:

paintNeeded = area/ sqftPerGallon

Since sqftPerGallon = 350 and area= 1000

paintNeeded = 1000 / 350

paintNeeded = 2.86

Hence the output of this part is:

Paint needed: 2.86 gallons

Next program computes cans needed as:

cansNeeded = int(math.ceil(paintNeeded))

This rounds the computed value of paintNeeded i.e. 2.86 up to nearest integer using math.ceil so,

cansNeeded = 3

Hence the output of this part is:

Cans needed: 3 can(s) Next program prompts user to choose a color to paint the wall

Lets say user chooses 'blue'

So the program get the cost corresponding to blue color and multiplies this cost to cans needed to compute the cost of purchasing blue paint per gallon cans. So

cost = cansNeeded * colorCost

cost = 3 * 25

cost = 75

So the output of this part is:

Cost of purchasing blue paint per 3 gallon can(s): $75 The screenshot of the program along with its output is attached.

5 0

3 years ago

Ways to ask for help effectively include

Step2247 [10]

Answer:

All of these choices

Explanation:

Clarity → the quality of being coherent and intelligible.

Sincerity → the quality of being free from pretense, deceit, or hypocrisy

Open mind → Open-mindedness is receptiveness to new ideas.

8 0

2 years ago

Add an array, which will store the most recent 5 recent transactions. For the array, add an insert function which will store the

Vika [28.1K]

The answer & explanation for this question is given in the attachment below.

Download docx

4 0

3 years ago

Which statement is true about customizing presentation programs? A. You can add multiple animations to an object in a slide with

levacccp [35]

From all the given options, the correct statement about customizing presentation is (B) you can customize a pre-designed slide layout with the Slide Master.

The option (A) is false, because if you want to put animations on your slide objects, you need to go to the Animation tab, while option (C) is false because to view the animation that you assign to a slide object, you need to open the animation pane bar or go to slide show. Option (D) is false because you can make changes to the colors, fonts, and effects for pre-designed slide themes.

6 0

3 years ago

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How many cubic millimeters are present in 0.0923 m3?​

How many cubic millimeters are present in 0.0923 m3?