Answer:
g = 5
Step-by-step explanation:
Expand brackets.
4g - 2 = 3g + 3
Add -3g and 2 on both sides.
4g - 3g = 3 + 2
Combine like terms.
1g = 5
It depends how many decimal points you are moving. If it's 1 decimal point then the point would move to the right and the answer would be 3246.50if it was two decimal places then it moves two to the right and the answer would 32465.0. But you don't need to put the .0 at the end so it will be 32465
x – 2y = 4
ax– 6y = 12
The second equation must has a value for a that makes the second equation equal to the first. In other words a has to be something that divides through the second equation to get the first.
The easiest way to proceed is to look at the right hand side. One equation has 12 on the right. The other has 4. What do you have to do to 12 to get it down to 4. I suppose you could subtract 8, but that would not apply to the left side.
The answer is divide 12 by 3.
If you do that then the 6 is divided by 3.
Find a
Now you need to consider a's value. It is either 1 or 3. If you choose 1, you will not be able to divide properly: dividing by 3 will leave you with 1/3.
The thing you must do is make a = 3
The second equation then becomes
3x - 6y = 12 Divide everything by 3
x - 2y = 12/3 = 4
Answer: a = 3
What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M
AURORKA [14]
<h3><u>given</u><u>:</u></h3>
<u></u>
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the mode and median of the given numbers set.
<h3><u>solution</u><u>:</u></h3><h3><u>mode</u><u>:</u></h3>
the most frequently occurred number.
<h3><u>median</u><u>:</u></h3>
first arrange all the numbers in either decending or ascending order, then find the number in the middle.
<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>median</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>following</u><u> </u><u>data</u><u> </u><u>set</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>mode</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>and</u><u> </u><u>3</u>
Answer: 40.2
Step-by-step explanation: