Answer:
Area for Triangle is: 1/2bh or bh/2
Area for Trapezoid (As shown in picture):
1/2h(b1+b2)
You’d have to do 1/2 x 18(15+37) for the quesyion in the picture
Hope this helped!
First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70 <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>
Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in
Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in
Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
Answer:
because of them is bigger than the other one so that means its differ but it has the same length
Step-by-step explanation:
Answer:
2677
Step-by-step explanation:
Let's make this easier first of all:
a^2-y^3(a-y^2)y^2
a^2-y^5(a-y^2)
a^2-ay^5+y^7
(-2)^2-(-2)(3)^5+3^7
4-(-2*243)+2187
4-(-486)+2187
4+486+2187
490+2187
2677
Step-by-step explanation:
|| represents the absolute value function:
|x| = x when x >= 0,
|x| = -x when x < 0.
Therefore (-8) * |2| = (-8) * 2 = -16. (A)
