Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5
Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students
Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students
Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68
Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
Answer:
i need this too
Step-by-step explanation:
Rational number is the term that describes 15/18
Answer:
Apply BODMAS
Step-by-step explanation:
PLEASE FIND THE PICTURE BELLOW
SOLUTION STEPS
(4⋅2−10x−24)(2x+3)
Multiply 4 and 2 to get 8.
(8−10x−24)(2x+3)
Subtract 24 from 8 to get −16.
(−16−10x)(2x+3)
Apply the distributive property by multiplying each term of −16−10x by each term of 2x+3.
−32x−48−20x
2
−30x
Combine −32x and −30x to get −62x.
−62x−48−20x
2
Answer:
The equation of the new function is y=5/3x+4
Step-by-step explanation:
y=5/3x
Shifted up (+) 4 units:
y=5/3x+4
