<span><span><span><span><span>14y</span>+112</span>+2</span>−<span>134y</span></span>−12</span><span>=<span><span><span><span><span><span><span>14y</span>+112</span>+2</span>+</span>−<span>134y</span></span>+</span>−12</span></span><span>=<span><span><span><span><span>14y</span>+112</span>+2</span>+<span>−<span>134y</span></span></span>+<span>−12</span></span></span><span>=<span><span>(<span><span>14y</span>+<span>−<span>134y</span></span></span>)</span>+<span>(<span><span>112+2</span>+<span>−12</span></span>)</span></span></span><span>=<span><span>−<span>120y</span></span>+102</span></span>
Answer:
<span>=<span><span>−<span>120y</span></span>+<span>102</span></span></span>
1 year = 3.6 % depreciation
100-3.6=96.4
so you do 35,865 ×0.964 = 34,573.86
so the price after a year is £34,573.86
to find out what the price is after 10 years you do 34,573.86 (0.964) to the power of 10
which equals £23961.73
I hope that was helpful :)
Answer:
The answer to this question is C
Answer:
v min (-2;-3)
Step-by-step explanation:
its going to be a parabola with a minimum of (-2;-3) I hope it helps
Answer: what are your options?
I would say 33=13
Step-by-step explanation:
