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qwelly [4]
3 years ago
11

Trying to help a friend

Mathematics
2 answers:
Julli [10]3 years ago
4 0
Answer: SAS

It just is
uranmaximum [27]3 years ago
3 0

Answer:

SAS

Step-by-step explanation:

Bro it's right

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I need help with this so could you give me the answers with an explanation if you can.​
Katarina [22]

Answer:

2.44745763 \times  {10}^{6}

Step-by-step explanation:

R =  \frac{ {x}^{2} }{y}  \\  \\  =  \frac{ {(3.8 \times  {10}^{5}) }^{2} }{5.9 \times  {10}^{4} }  \\  \\  =  \frac{14.44 \times  {10}^{10} }{5.9 \times  {10}^{4} }  \\  \\  = 2.44745763 \times  {10}^{10 - 4}  \\ = 2.44745763 \times  {10}^{6}

4 0
3 years ago
1+1<br><br>Plz give good reasoning why this is an snwer
Dahasolnce [82]

Answer: 1+1 is equal to 2, because adding a singular object to a specified amount of something to the number 1, it will increase by just that. Therefore, if the quantity of something is one, adding the number one to its value will be the number 2.

6 0
3 years ago
write the standard form of the line that passes through the given points include your work in your final answer type your answer
Gemiola [76]
The slope is change in "Y" divided by the change in "x"
1-(-3)/2-(-1)
 = 4/3

Standard Form
y-y1=m(x-x1)
y-(-3)=4/3(x-(-1)
y+3=4/3x+4/3
y=4/3x-5/3

Rewrite in standard form
-4/3x+y=-5/3
Can't have fractions so multiply by 3 to get rid of the denominator
-4x+3y=5
Divide by -1 to get rid of the negative sign

4x-3y=-5


4 0
3 years ago
$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed t
Neporo4naja [7]

Answer:

The interest needed to reach that value of $6000 is 2.75%

Step-by-step explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

<u>From Compound Interest method</u>

Amount = principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, $6000 = $4000 × (1+\dfrac{\textrm r}{100})^{\textrm 15}

or, \dfrac{6000}{4000} = (1+\dfrac{\textrm r}{100})^{\textrm 15}

Or, \frac{3}{2} = (1+\dfrac{\textrm r}{100})^{\textrm 15}

or, 1.5 = (1+\dfrac{\textrm r}{100})^{\textrm 15}

or, 1.5^{\frac{1}{15}} = (1+\dfrac{\textrm r}{100})

or, 1.0275 =  (1+\dfrac{\textrm r}{100})

or, 1.0275 - 1 = \dfrac{r}{100}

or, 0.0275 = \dfrac{r}{100}

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

3 0
3 years ago
Given the equation 6(3 + 2x) = 54, which of the following equations are equivalent?
gizmo_the_mogwai [7]

Answer:

answer for this solution is 2,3,4.

8 0
3 years ago
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