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2 years ago

5/12 + 2/3 Please help

Mathematics

2 answers:

AnnZ [28]2 years ago

6 0

Answer:

The answer is 1 and 1/12 you can’t simplify the problem but this is the answer

Step-by-step explanation:

aleksandr82 [10.1K]2 years ago

3 0

Answer:

1 1/2

Step-by-step explanation:

We make 2/3 equal 5/12 to we do multiply 4 to 3 and 4 to 2 which then is 8/12 and 8+5 is 13/12 which goes to one and one half

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Julian fully simplifies this polynomial and then writes it in standard form. 4x2y2 – 2y4 – 8xy3 + 9x3y + 6y4 – 2xy3 – 3x4 + x2y2

ollegr [7]

Given that the last term is -3x^4, the polynomila is ordered in descending order of the exponent of x. Then, the first term is that where y is with the highest exponent, that is y^4

Simplify the terms with y^4: -2y^4 + 6y^4 = 4y^4

Then the first term is 4y^4

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3 years ago

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HALP ASAP!!! 10 POINTS

guajiro [1.7K]

Answer:

The answer is b

Step-by-step explanation:

3 0

2 years ago

Help I don't understand this, Can someone explain this to me?

saul85 [17]

Answer:

The second answer is correct (5 x 1,000,000,000)

Step-by-step explanation:

Just count the number of zeros. Multiplying a number liket his by five doesn't change the number of zeros

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2 years ago

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The number and frequency of Atlantic hurricanes annually from 1940 through 2007 is shown here:

klio [65]

Answer:

The probability table is shown below.

A Poisson distribution can be used to approximate the model of the number of hurricanes each season.

Step-by-step explanation:

(a)

The formula to compute the probability of an event E is:

$P(E)=\frac{Favorable\ no.\ of\ frequencies}{Total\ NO.\ of\ frequencies}$

Use this formula to compute the probabilities of 0 - 8 hurricanes each season.

The table for the probabilities is shown below.

(b)

Compute the mean number of hurricanes per season as follows:

$E(X)=\frac{\sum x f_{x}}{\sum f_{x}}=\frac{176}{68}= 2.5882\approx2.59$

If the variable X follows a Poisson distribution with parameter λ = 7.56 then the probability function is:

$P(X=x)=\frac{e^{-2.59}(2.59)^{x}}{x!} ;\ x=0, 1, 2,...$

Compute the probability of X = 0 as follows:

$P(X=0)=\frac{e^{-2.59}(2.59)^{0}}{0!} =\frac{0.075\times1}{1}=0.075$

Compute the probability of X = 1 as follows:

$\neq P(X=1)=\frac{e^{-2.59}(2.59)^{1}}{1!} =\frac{0.075\times7.56}{1}=0.1943$

Compute the probabilities for the rest of the values of X in the similar way.

The probabilities are shown in the table.

On comparing the two probability tables, it can be seen that the Poisson distribution can be used to approximate the distribution of the number of hurricanes each season. This is because for every value of X the Poisson probability is approximately equal to the empirical probability.