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Scilla [17]
3 years ago
12

Does anyone know the answer?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0

Answer:

a = √5

b ∈ (−∞,∞)

Step-by-step explanation:

(7 + 3√5)/(3 + √5) - (7 - 3√5)/(3 - √5) = a + b√5

⇔ (7 + 3√5)(3 - √5)/(3 + √5)(3 -√5) - (7 - 3√5)(3 + √5)/(3 + √5)(3 -√5) = a + b√5

⇔ (7 + 3√5)(3 - √5) -  (7 - 3√5)(3 + √5)/(3 + √5)(3 -√5) = a + b√5

⇔ 4√5/4 = a + b√5

⇔ √5 = a + b√5

⇔ b = (5 - a√5)/5

Replace b with (5 - a√5)/5

⇒ a +  (5 - a√5)/5 = √5

⇔ a × 5 + (5 - a√5)(5)/5 = √5 × 5

⇔ a × 5 + 5 - a√5 = 5√5

⇔ a × 5 - √5 × a = 5√5 - 5

⇔ a(5 - √5) = 5√5 - 5

⇔ a = √5

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Help me with this please ​
Tom [10]

Answer:

neither

Step-by-step explanation:

4 0
3 years ago
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NEED HELP ASAP! Arianna correctly simplified an expression. When she substituted \ into the simplified expression, the value was
erastova [34]

Answer:

<em>(1/6)(-10x - 4) = -4 </em>

Step-by-step explanation:

(1/6)(-3x - 24) = -4

=> -3x - 24 = -4 x 6

=> -3x - 24 = -24

=> -3x = 24 - 24

=> -3x = 0

=> x = 0 (not 2) => Incorrect option

(1/6)(-5x - 8) = -4

=> -5x - 8 = -4 x 6

=> -5x - 8 = -24

=> -5x = 8 - 24

=> -5x = -16

=> x = 16/5 (not 2) => Incorrect option

(1/6)(-10x - 4) = -4

=> -10x - 4 = -4 x 6

=> -10x - 4 = -24

=> -10x = 4 - 24

=> -10x = -20

=> x = 2 => Correct option

(1/6)(-12x - 16) = -4

=> -12x - 16 = -4 x 6

=> -12x - 16 = -24

=> -12x = 16 - 24

=> -12x = 8

=> x = -3/4 (not 2) => Incorrect option

=> Option C is correct

Hope this helps!

3 0
4 years ago
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In order to estimate the average time spent on the computer terminals per student at a local university, data were collected for
Setler [38]

Answer:

7) d)

standard error of the mean of one sample of 'n' observation = 0.20

8) a)

The margin of Error = 0.392

9) d

The 95% of confidence intervals are (8.61 , 9.39)

Step-by-step explanation:

7)

solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

The standard error of the mean of one sample of 'n' observation is

Standard error (SE)

                               = \frac{S.D}{\sqrt{n} }  

                               = σ / √n

                               = \frac{1.8}{\sqrt{81} } =0.2

standard error of the mean of one sample of 'n' observation = 0.20

8)

Solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

Given the probability is 0.95

The z- score = 1.96 at 0.05 level of significance.

The margin of Error   =  \frac{z_{0.95} S.D}{\sqrt{n} }

                                   = \frac{1.96 (S.D)}{\sqrt{n} }

                                   = \frac{1.96 (1.8)}{\sqrt{81} }

                                   = 0.392

The margin of Error = 0.392

9)

Solution:-

<u>The 95% of confidence intervals are </u>

<u></u>(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96\frac{S.D}{\sqrt{n} } )<u></u>

<u></u>(9 - 1.96\frac{1.8}{\sqrt{81} } , 9+ 1.96\frac{1.8}{\sqrt{81} } )<u></u>

(9 - 0.392 , (9 + 0.392)

(8.609 , 9.392)

<u>The 95% of confidence intervals are </u>(8.61 , 9.39)

 

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