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STALIN [3.7K]
3 years ago
10

Ted and Fred are the owners of a gas station. They invested $150,000 each and pay an employee named Lawrence $35,000 per year. T

his year revenues are $900,000, while costs are $940,000. Who is legally responsible for bearing the $40,000 loss?
Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

Ted and Fred

Step-by-step explanation:

As per the question,

Ted and Fred are the owners of a gas station that is they are the owner of their own firm.

As being the owner of their own company, they are the one who is responsible for their loss. That is the firm’s owners always suffer the firm’s risk.

Business Risk: Risk that a business will not be able to cover its operating costs.

So in this case, Lawrence is the employee and legally he is not responsible to suffer any kind of the loss.

So he must be paid his salary  on time and in full whether or not the firm is running a profit, a loss, or just breaking  even.

As being owner Ted and Fred are responsible to withstand the business risk.

Hence, the person who is legally responsible for bearing the $40,000 loss is Ted and Fred.

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A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

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C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
3 years ago
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