Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
9514 1404 393
Answer:
{4, 5, 6, 7, 8}
Step-by-step explanation:
The inequality related to the perimeter is ...
x +(x +4) +11 < 32
2x < 17 . . . . . . . . . . . . subtract 15
x < 8.5
The inequality related to the triangle inequality is ...
(x) +(x +4) > 11
2x > 7
x > 3.5
Then possible whole-number values of x are ...
{4, 5, 6, 7, 8}
Answer:
48 - 40 = $8, there is a $8 dollar increase.
Formula for change of percentage;
changed price
___________ x 100% (100/100)
original amount
Replace those values with the values we found;
40/48 x 100/100 = 20% increase.
9×8-29+30/15-15 equals 30
Answer:Yes
Step-by-step explanation:
5×3=15. 9×3=27
