First, you have to find the equation of the perpendicular bisector of this given line.
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10 (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)
now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line.
try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint.
Answer: 2.9 ≠ −7 (False)
Step-by-step explanation:
Answer:
VT = 50√3 , PT = 50
Step-by-step explanation:
Given
PV = 100
With reference angle 60°
hypotenuse (h) = 100
perpendicular (p) = ?
Now
Sin 60° = p/h
√3 / 2 = p / 100
p = √3 * 100 / 2
p = 50√3
Also
With reference angle 30°
hypotenuse (h) = 100
perpendicular (p) = ?
sin 30° = p/h
1/2 = p / 100
p = 100 / 2
p = 50
Hope it will help :)
Answer:
y = -1/3x + 4
Step-by-step explanation:
y = 3x +5
current slope m is 3, perpendicular is opposite inverse which is -1/3
Passing through (6,2):
y = mx + b
2 = -1/3(6) + b
2 = -2 + b
b = 4
Use the perpendicular m = -1/3 and b = 4 to form equation of line:
y = mx + b
y = -1/3x + 4
there are 360 degress in a circle if you cut a circle in half at its center aka its diameter the center angle would be 180 degree or a straight line 360/2 180 and a circle divide into 2 sectors so your questoin would be equal algebraically to 360x=30 360 is the totatal number degrees in every circle 30 is the resulting degree and x is the length of each of the sectors if you solve yo get 1/12 thus total sectors would be 12
