Which expression is equivalent to the perimeter expression?

the $700 you put into the bank is being continuously at 1.2%. how much will it be worth after 3 years?

Olin [163]

Answer:

$983.45

Step-by-step explanation:

Given data

Principal= $700

Rate= 1.2%

Time= 3 years

The compound interest expression is given as

A= P(1+r)^t

A= 700(1+0.12)^3

A= 700(1.12)^3

A= 700*1.404928

A=$983.45

Hence the balance will be $983.45

7 0

3 years ago

HELP ASAP PLEASE AND THANKS IN ADVANCED....I NEED TO GET THIS DONE !!!!!!!!!

AVprozaik [17]

I think b is the answer

8 0

3 years ago

1. Remember what we know about vertical angles and solve for x. (SHOW WORK)

EastWind [94]

Answer:

Ans.1.) X = 7.

Ans.2.a.) AC =JL.

Ans.2.b.) BC = KL.

Step-by-step explanation:

For Question 1.

As we know vertically opposite angles are equal.

$\therefore (x+16)\° = (4x-5)\°\\\therefore (5+16)\° = (4x-x)\°\\ \therefore (3x) = (21)\\\therefore x = 7\\$

For Question 2.a)

$In\ \triangle ABC and \triangle JKL \\AB \cong JK\ \textrm{Given}\\\angle CAB \cong \angle LJK\ \textrm{each measure angle of 90\°}\\AC \cong JL\ \textrm{this is the required information to prove the triangles are congruent by SAS postulate}\\\therefore \triangle ABC \cong \triangle JKL\ \textrm{ By SAS postulate}$

For Question 2.b)

$In\ \triangle ABC and \triangle JKL \\AB \cong JK\ \textrm{Given}\\\angle CAB \cong \angle LJK\ \textrm{each measure angle of 90\°}\\BC \cong KL\ \textrm{this is the required information to prove the triangles are congruent by HL Theorem}\\\therefore \triangle ABC \cong \triangle JKL\ \textrm{ By Hypotenuse length Theorem}$

3 0

2 years ago

Assume that females have pulse rates that are normally distributed with a mean of beats per minute and a standard deviation of b

snow_tiger [21]

Answer:

a) This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b) P-value of Z when X = 76 subtracted by the p-value of X = 68.

c) Because the underlying distribution(pulse rates of females) is normal.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$ .

standard deviation of beats per minute.

a. If 1 adult female is randomly selected, find the probability that her pulse rate is between A beats per minute and B beats per minute.

This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b. If 4 adult females are selected, find the probability that they have pulse rates with a mean between 68 beats per minute and 76 beats per minute.

Sample of 4 means that we have $n = 4, s = \frac{\sigma}{\sqrt{4}} = 0.5\sigma$