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kirza4 [7]
3 years ago
12

Can someone please help me on this and show work if you can? Thanks!

Mathematics
1 answer:
Aneli [31]3 years ago
5 0

Answer:

area = 18.81 m²

Step-by-step explanation:

solving for the 7 sided polygon first:

divide into 7 equal isosceles triangles, each having sides of 10 m and a peak angle of 360°/7 = 51.43°. Drop a line from the peak & perpendicular to the base makes a right triangle with a 25.71° peak angle and a 10 m hypotenuse.

sin 25.71° = x/10, x = 4.34, the base of the full triangle will be 2 x 4.34 = 8.68 m

cos 25.71° = x/10, x = 9.01, the rise of the triangle is 9.01 m

The area of each triangle will be 1/2(8.68)(9.01) = 39.10 m²

39.10 x 7 triangles = 273.72 m²

area of 7 sided polygon = 273.72 m²

Next solve for the inner circle:

The rise of the triangle (9.01) is the radius of the inner circle.

area of inner circle = πr² = 3.14(9.01²) = 254.91 m²

273.72 - 254.91 = 18.81 m²

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4 years ago
-a^2+46a-480=0<br> a - ?
sattari [20]
a = 30
a = 16

-a² + 46a -480 = 0

(-a + 30) (a -16) = 0
(-a)(a) + (-a)(-16) + 30(a) + 30(-16) = 0
-a² + 16a + 30a -480 = 0
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(-a + 30) = 0   ; (a - 16) = 0
-a = -30          ;   a = 16
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To check:
a = 30
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3 years ago
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Serggg [28]

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3 years ago
Find the sum of the first 30 terms of the equation below: an=4n+1
Alex73 [517]
Let n = 30

We are actually looking for a_30.

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