I would help but I'm not sure what you are asking for us to do
Answer:
Options (1), (3), (5) and (6)
Step-by-step explanation:
Option (1)
Both the circles M and H are same in shape. Therefore, both are similar.
True
Option (2)
MH = MS = [Radii of a circle]
MH = MO + OH
MH = ME + OH [Since, MO = ME]
MH = 10 + 25 = 35 cm
Area of circle M = πr²
= π(35)²
= 1225π
Area of circle H = π(25)²
= 625π

Area of M = 1.96(Area of H)
False
Option 3
OH + MS = 25 + 35
= 60 cm
True
Option 4
m∠HMS = 90°
Can't be figured out with the given informations
False
Option 5
Diameter of circle H = 2(radius)
= 2(25)
= 50 cm
True
Option 6
Circumference of circle S = 2πr
= 2π(ES)
Circumference of circle M = 2π(MS)
Ratio of the circumference of circle S and M = 
= 
True.
Options (1), (3), (5) and (6) are correct.
Answer: yes
Step-by-step explanation:
X^5 (X to the fifth power) - 4 (x^5 - 4)
Answer:
its alot to explain but i will try to make it as simple as possible
Step-by-step explanation:
your first goal is to make each problem into the form ax^2+bx+c=0
number 1, 2, 7 and 8 is already done for you
now all you have to do is plug in each number in the standard form into the quadtratic formula.
basically at this point you can just use your calculator to do the rest of the work. dont forget parentheses so it doesnt get confused...
or you can perform the algebraic work.. its all just a matter of plugging in the right numbers into the quadratic formula...
cant really do the work for you since im on my phone. but yeah all you need to do step one is transform each problem into ax^2+bx+c=0 form
then step 2, plug in each number in to the quadtratic formula. from there calculate using basic algebraic rules