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Butoxors [25]
3 years ago
6

What is the solution to the equation A + 5 2/3 = 9​

Mathematics
1 answer:
natulia [17]3 years ago
6 0

Answer:

the first one is your answer

Step-by-step explanation:

I hope it help ^_^

have a great day!!

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Compared to others, which one of the following is not robust to outliers? a) Mean b) Median c) Mode d) 50th percentile
tatyana61 [14]

Answer:

The mean.

Step-by-step explanation:

The mean is not robust.

The presence of an outlier greatly affects the value of a mean.

An example will illustrate this.

Find the mean of  the numbers   2  3  5  6  34.

34 is an outlier. The mean = (2+3+5+6+34) / 5 = 10.

Now   if we replace the outlier with a number closer to the others:

Say we have 2 3 5 6 8 :

The mean = (2+3+5+6+8) / 5 =  4.8 which is a much truer measure of centrality than 10.

3 0
3 years ago
Blain is two years older than three times Jillians age. Jillian is also 16 years younger than Blain. How old is Blain?
Ipatiy [6.2K]

The age of Blain is 23 years old

<h3><u>Solution:</u></h3>

Let the age of Blain be "a" and age of Jillian be "b"

Given that Blain is two years older than three times Jillians age

So we can frame a equation as:

age of blain = 2 + 3(age of Jillian)

a = 2 + 3b ----- eqn 1

Also given that Jillian is also 16 years younger than Blain

Age of Jillain = Age of Blain - 16

b = a - 16 ---- eqn 2

Substitute eqn 2 in eqn 1

a = 2 + 3(a - 16)

a = 2 + 3a - 48

a - 3a = -46

-2a = -46

a = 23

Thus the age of Blain is 23 years old

4 0
3 years ago
Macon eats 33 animal crackers as a snack every day after school. how many animal crackers does she eat during a 5 day school day
Pavlova-9 [17]

Answer:

165 crackers.

Step-by-step explanation:

33x5=165 crackers

3 0
3 years ago
According to a certain website, wine critics generally use a wine-scoring scale to communicate their opinions on the relative qu
const2013 [10]

Answer:

\bar x = 82

\sigma =  9.64

Step-by-step explanation:

Given

n = 12

87\ 91\ 86\ 82\ 72\ 91\ 60\ 77\ 80\ 79\ 83\ 96

Solving (a); Point estimate of mean

To do this, we simply calculate the sample mean

\bar x = \frac{\sum x}{n}

\bar x = \frac{87+ 91+ 86+ 82+72+91+60+77+80+79+83+96}{12}

\bar x = \frac{984}{12}

\bar x = 82

Solving (b); Point estimate of standard deviation

To do this, we simply calculate the sample standard deviation

\sigma = \sqrt{\frac{\sum(x-\bar x)^2}{n - 1}

\sigma = \sqrt\frac{(87-82)^2+ (91-82)^2+ ....+ (79-82)^2+ (83-82)^2+ (96-82)^2}{12-1}

\sigma = \sqrt\frac{1022}{11}

\sigma = \sqrt{92.91}

\sigma =  9.64

<em>Note that: The sample mean and the sample standard deviation are the best point estimators for the mean and the standard deviation, respectively.</em>

<em>Hence, the need to solve for sample mean and sample standard deviation</em>

3 0
3 years ago
Please help with this question
12345 [234]
A^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
25 = c^2
5 = c
5 0
3 years ago
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