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antiseptic1488 [7]

3 years ago

7

Stephanie has 3.5 bags of soil to put in her garden. Each bag of aoil will cover 125.3 ft2. How many square feet will stephanie

be able to cover if she uses all these bags of soil?

2 answers:

NARA [144]3 years ago

7 0

Answer:

438.55 ft²

Step-by-step explanation:

1 bag = 125.3 ft²

3.5 bags = 125.3 • 3.5 ft²

= 438.55 ft²

astraxan [27]3 years ago

7 0

Answer:

Step-by-step explanation:

125.3*3.5

438.55

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a bug population doubles every 5 days. If you start with 6 bugs, how many bugs will there be in 35 days

Shtirlitz [24]

Answer:

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Step-by-step explanation:

You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.

f(x)=6*2^(x/5)

Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.

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Answer: The correct answer is B.

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2 years ago

Solve for y<br> 2(3 + 3y) + y = 11

garik1379 [7]

<h2><u>EQUATION</u></h2><h3>Exercise</h3>

2(3 + 3y) + y = 11

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2(3 + 3y) + y = 11

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6 + 7y = 11

Substract 6 from both sides:

6 - 6 + 7y = 11 - 6

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Divide both sides by 7:

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3 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

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