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AlexFokin [52]
2 years ago
15

Shama types 12 letters in 4 secound what is the constant of proportionality of letters to minutes

Mathematics
2 answers:
aleksley [76]2 years ago
7 0
Answer is 3

Since we know the shama has typed 12 letters in 4 seconds so that 12 divide 4 equal 3
Galina-37 [17]2 years ago
4 0

Answer:

I think its 3, but if I'm wrong I'm so sorry!

Step-by-step explanation:

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Simplify the following expression
Kay [80]

Answer:

\frac{98p^{6}}{q}

Step-by-step explanation:

Distribute the exponents

(\frac{(7^{-2}p^{-6}q^{-8})}{2q^{-9}} )^{-1}

(\frac{q}{98p^{6}} )^{-1}

Distribute the -1

\frac{98p^{6}}{q}

6 0
3 years ago
charlie charted the rainfall in abilene over a one year period. what is the difference between the median and the mode of the da
sveticcg [70]
3.14•8=B because it is the median
7 0
3 years ago
What is the decimal 25/75
Charra [1.4K]

Answer:

0.3

Step-by-step explanation:

1. break it down 25/75

2. the answer 1/3 not the real answer

3.turn decimal form

4.  0.3

3 0
2 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
2 years ago
How do I do this problem I am stuck .
marta [7]
1) Add 9 to both sides. On the left side of the equal sign it will cancel out. on the right side of the equal sign because it is now a different sign equation you subtract -193 from 9 which equals -184
2) now you are left with to= -184
to get the variable by itself you need to divide both sides by 4. on the left side of the equal sign you have p by itself now , on the right you divide -184 by 4 and your answer comes out to be p= -46
3) p= -46 is your final answer!
7 0
3 years ago
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