I just need these two done. tysm!!

How do you solve 1. X^2-x+1=0 2. X^2-2x+5=0 In the complex number system ?

Alexxandr [17]

You use the discriminant (b²-sqr(4ac))/2a and if sqr(4ac) inferior to 0 then use i = sqr(-1)

8 0

3 years ago

The fee to join the community baseball league is $34.25. However, if you are a returning member to the league, you receive a dis

USPshnik [31]

Answer:

21.75

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The area of shaded region.

Korvikt [17]

Answer:

160π cm²

Step-by-step explanation:

The area of the shaded region is

area of outer circle - area of inner circle

A = πr₁² - πr₂²

r₁ is the radius of the outer circle = 10 + 3 = 13 cm

r₂ is the radius of the inner circle = 3 cm

A = π × 13² - π × 3²

= π(169 - 9) = 160π cm² ≈ 502.65 cm² ( to 2 dec. places )

5 0

3 years ago

Read 2 more answers

The diagram shows how cos θ, sin θ, and tan θ relate to the unit circle. Copy the diagram and show how sec θ, csc θ, and cot θ r

DIA [1.3K]

Copy the diagram and show how sec θ, csc θ, and cot θ relate to the unit circle.

The representation of the diagram is shown if Figure 1. There's a relationship between sec θ, csc θ, and cot θ related the unit circle. Lines green, blue and pink show the relationship.

a.1 First, find in the diagram a segment whose length is sec θ.

The segment whose length is sec θ is shown in Figure 2, this length is the segment $\overline{OF}$ , that is, the line in green.

a.2 Explain why its length is sec θ.

We know these relationships:

(1) $sin \theta=\frac{\overline{BD}}{\overline{OB}}=\frac{\overline{BD}}{r}=\frac{\overline{BD}}{1}=\overline{BD}$

(2) $cos \theta=\frac{\overline{OD}}{\overline{OB}}=\frac{\overline{OD}}{r}=\frac{\overline{OD}}{1}=\overline{OD}$

(3) $tan \theta=\frac{\overline{FD}}{\overline{OC}}=\frac{\overline{FC}}{r}=\frac{\overline{FC}}{1}=\overline{FC}$

Triangles ΔOFC and ΔOBD are similar, so it is true that:

$\frac{\overline{FC}}{\overline{OF}}= \frac{\overline{BD}}{\overline{OB}}$ 

∴ $\overline{OF}= \frac{\overline{FC}}{\overline{BD}}= \frac{tan \theta}{sin \theta}= \frac{1}{cos \theta} \rightarrow \boxed{sec \theta= \frac{1}{cos \theta}}$ 

b.1 Next, find cot θ

The segment whose length is cot θ is shown in Figure 3, this length is the segment $\overline{AR}$ , that is, the line in pink.

b.2 Use the representation of tangent as a clue for what to show for cotangent.

It's true that:

$\frac{\overline{OS}}{\overline{OC}}= \frac{\overline{SR}}{\overline{FC}}$

But:

$\overline{SR}=\overline{OA}$
$\overline{OS}=\overline{AR}$

Then:

$\overline{AR}= \frac{1}{\overline{FC}}= \frac{1}{tan\theta} \rightarrow \boxed{cot \theta= \frac{1}{tan \theta}}$

b.3 Justify your claim for cot θ.

As shown in Figure 3, θ is an internal angle and ∠A = 90°, therefore ΔOAR is a right angle, so it is true that:

$cot \theta= \frac{\overline{AR}}{\overline{OA}}=\frac{\overline{AR}}{r}=\frac{\overline{AR}}{1} \rightarrow \boxed{cot \theta=\overline{AR}}$

c. find csc θ in your diagram.

The segment whose length is csc θ is shown in Figure 4, this length is the segment $\overline{OR}$ , that is, the line in green.

3 0

4 years ago

Brian and Jennifer are planning to get married at the end of the year. They read that certain diets are healthier for specific b

Eva8 [605]

D dnbdsjhdjshshdhdjdhdjdjjdjd you gotta give more points if u want sum 1 to actually answer

7 0

3 years ago