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3 years ago

Write the sum of the numbers as the product of their gcf and another sum 32 and 20

Mathematics

1 answer:

pav-90 [236]3 years ago

7 0

Ymm makes no sense but its pulsing so yea the answer is 52

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5,140 centimeters = decameters centimeters

Ahat [919]

Answer:

5.14 Decameters

hope it helps

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3 years ago

Let f(x)=3x-7 and g(x)=2x². Perform the function operation and then find the domain of the result.

olya-2409 [2.1K]

Answer: A

Step-by-step explanation:

$f(x)=3x-7\\g(x)=2x^2$

$(f-g)(x)=3x-7-(2x^2)\\(f-g)(x)=3x-7-2x^2\\(f-g)(x)=-2x^2+3x-7$

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3 years ago

Name two points that determine line AC.

Bogdan [553]

Answer: A & C

Step-by-step explanation:

4 0

3 years ago

Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re

kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read $13\frac{3}{4}$ pages in $\frac{1}{4}$ of an hour.

Therefore, pages read by Zander in 1 hour = $\frac{\text{Total pages read}}{\text{Total time taken}}$

= $\frac{13\frac{3}{4}}{\frac{1}{4}}$

= $\frac{55}{4}\times \frac{4}{1}$

= 55 pages per hour

Sydney read $43\frac{1}{3}$ pages in $\frac{2}{3}$ of an hours.

Pages read by Sydney in 1 hour = $\frac{43\frac{1}{3}}{\frac{2}{3} }$

= $\frac{130}{3}\times \frac{3}{2}$

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0

3 years ago

If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v

pochemuha

Answer:

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = $5000(1 - \frac{1}{40}t )^2$ , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = $2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )$

V'(t) = $2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )$

When we simplify the above, we get

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

4 0

4 years ago