Idk...
what did the doctor say?
The inscribed angle theorem says that

Triangle AOC is isosceles because both AO and CO are radii of the circle and have the same length. This means angles CAO and ACO have the same measure and are congruent.
Angles ACO and COD are congruent because they form an alternating interior pair between the parallel lines AC and OD.
Taking all these facts together, we have

and since angle COB is made up of angles COD and DOB, these angles must be congruent, and so the arcs they subtend (CD and DB, respectively) must also congruent.
Line 1:
Expanding the vertex form, we have
x² + 2·1.5x + 1.5² - 0.25 = x² +3x +2
Expanding the factored form, we have
x² +(1+2)x +1·2 = x² +3x +2
Comparing these to x² +3x +2, we find ...
• the three expressions are equivalent on Line 1
Line 2:
Expanding the vertex form, we have
x² +2·2.5x +2.5² +6.25 = x² +5x +12.5
Expanding the factored form, we have
x² +(2+3)x +2·3 = x² +5x +6
Comparing these to x² +5x +6, we find ...
• the three expressions are NOT equivalent on Line 2
The appropriate choice is
Line 1 only
Answer: 8√3
<u>Step-by-step explanation:</u>
ΔXVW is a 30°-60°-90° triangle. This special triangle has corresponding sides of lengths: b - b√3 - 2b. So,
VW = b
XW = b√3
XV = 2b
Since, YV = 24, then XW = 24 and we stated above that XW = b√3. So,
24 = b√3

= b
= b
= b
8√3 = b
We are looking for side YX which is congruent (equal) to VW and we stated above that VW = b, So, VW = 8√3