Answer:
Percent error = -4.02 (Approx.)
Step-by-step explanation:
Given:
Estimated pool dimension = 15 ft long and 35 ft wide
Actual pool dimension = 14.5 ft long and 34.75 ft wide
Find:
Percent error
Computation:
Area of Estimated pool = 15 x 35
Area of Estimated pool = 525 ft²
Area of Actual pool = 14.5 x 34.75
Area of Actual pool = 508.875 ft²
Percent error = [(Actual - Estimated) / Estimated]100
Percent error = [(508.875 - 525) / 525]100
Percent error = [(-21.125) / 525]100
Percent error = -4.02 (Approx.)
Answer:
135ft²
Step-by-step explanation:
Width = w
Length = w + 6
Perimeter = 48
Perimeter = 2(l + w)
Perimeter = 2(w + 6 + w) = 48
2(2w + 6) = 48
4w + 12 = 48
4w = 48 - 12
4w = 36
w = 36/4
width = 9
length = w + 6 = 9 + 6 = 15
Area = length × width
= 15 × 9
= 135 ft²
D . A cube that is 1 inch long , 1inch wide and 1 inch high .
Answer
its a cube whose side is 1 unit long .
And total surface area should be 6 square units .
as we can see
Answer:
All angles must add up to 180, so if you add 69+5x+2+9y-3, it is = to 180.
First we can subtract 68 cancelling out 69, 2 and -3 so it is
5x+9y = 112. I assume this is an iscoceles triangle so we already knew 9y - 3 = 69, y=8, x=8
I have solved the first one. Hope this helps
