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bezimeni [28]
3 years ago
8

Find the area inside the semicircle and out side the triangle in terms of ń

Mathematics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

π 169 / 2 - 120

Step-by-step explanation:

I'm assuming you are asking question about 24.

So first find radius of semicircle:

a^2+b^2=c^2

10^2+24^2=c^2

c=26

radius 26/2 = 13

Then let's calculate area of semicircle

area of circle = π*r^2

area of semicircle = π*r^2 / 2

area of given semi circle = π 169 / 2

Then let's calculate area of triangle

area of triangle = 10 * 24 / 2 = 120

Area of the shaded region =  π 169 / 2 - 120

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6-x=9 how do you find x
podryga [215]

Answer:

15

Step-by-step explanation:

1- 6-x=9 Place the terms on the correct side; always place terms with x on the left hand side and the others on the right hand side. (when placing on the other side convert from + to - or reversed) (the 6- converted to 6+)

2- x= 6+9= 15 Now work out the sum.

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6 0
3 years ago
Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

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3 years ago
What is the solution to this equation 1/2n^2+18=0
ololo11 [35]

Answer:

n = ±6 .

Step-by-step explanation:

A quadratic equation is given to us and we need to find out the solution of the given equation . The given equation is ,

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\rm\implies -\dfrac{1}{2}n^2 = -18

Multiplying both sides by -2 ,

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On simplyfing , we get ,

\rm\implies n^2= 36

Putting squareroot both sides ,

\rm\implies n= \sqrt{36}

This equals to ,

\rm\implies \boxed{\quad\blue{\rm n =\pm 6 }}

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>n </u><u>is </u><u>±</u><u>6</u><u> </u><u>.</u>

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3 years ago
What is 3/8 in decimal form
forsale [732]
Simple; you want to divide 3 and 8.

3 / 8 = 0.375

And there's your answer! Remember that a fraction is just a fancy division problem! :)
4 0
3 years ago
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