Answer:

Step-by-step explanation:
Given the expression

Let us perform the operation and express your answer as a single fraction



Therefore, we conclude that:

The square root of -15 is 3.87298335
Answer:
For maximum area, all of the wire should be used to construct the square.
The minimum total area is obtained when length of the wire is 10m
Step-by-step explanation:
For maximum, we use the whole length
For minimum,
supposed the x length was used for the square,
the length of the side of the square = x/4m
Area =
For the equilateral triangle, the length of the side = 
Area = 
Total Area =
+ 

, therefore it is minimum


x = 10.00m
Two solutions:
1. x =(100-√2160)/2=50-6√ 15 = 26.762
2. x =(100+√2160)/2=50+6√ 15 = 73.238
The answer would be 37 I hope this helped