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klasskru [66]
3 years ago
9

Subtract (5y3 + 6y + 3y4) from (4y4 - 8y3). With step by step work***

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0

  4y⁴ - 8y³ - (5y³ + 6y + 3y⁴)

= 4y⁴ - 8y³ - 5y³ - 6y - 3y⁴

= (4y⁴  - 3y⁴) + (- 8y³ - 5y³) - 6y

= y⁴ - 13y³ - 6y

Answer:  y⁴ - 13y³ - 6y

Alexxx [7]3 years ago
8 0

Answer:

y4 - 13y3 - 6y

Step-by-step explanation:

(4y4 - 8y3)−(5y3 + 6y + 3y4)

-4x4 − 8y3 − 5y3 − 6y − 3y4

y4 - 13y3 - 6y

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