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1 year ago

Why do you praise role of decomposers

1 answer:

6 0

Decomposers take away all of the earth natural “trash” and turns it back into nutrients for the plants. So in the food chain we have plant->prey->predator->then the decomposers take the (dead) predator and turn it into to nutrients for the plants. Of course you can count all the other dead things as well, not just predators. Imagine if every time you killed a bug in your house and you didn’t pick it up how many dead bugs there would be laying around, it would be like this but on a much much larger scale.

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How does the heart pump blood from the right ventricle to the lungs and the left ventricle to the rest of the body? (mention the

netineya [11]

The right ventricle pumps the oxygen-poor blood to the lungs through the pulmonary valve. The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle through the mitral valve. The left ventricle pumps the oxygen-rich blood through the aortic valve out to the rest of the body.

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2 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

aleksandr82 [10.1K]

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Explanation:

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2 years ago

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rewona [7]

hope this helps u to understand.

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2 years ago

Read 2 more answers

Me pueden ayudar con la respuesta? Es urgente!

Ann [662]

A: especie

B: gen

C: desarollo

E:deriva genetica

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2 years ago

scalloped (sd) is an X-linked recessive and ebony (e) is an autosomal recessive mutation. What proportion of scalloped, ebony fe

alisha [4.7K]

Answer:

1/16

Explanation:

scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
ebony (e) is an autosomal mutation recessive to e+ (wild type).

The two genes are independent because they are located on different chromosomes.

<h3>Parental generation:</h3>

True breeding scalloped female wild type for ebony (Xsd Xsd e+e+) mates with a true breeding male mutant only for ebony (Xsd+ Y ee).

The female only produces Xsd e+ gametes. The male produces Xsd+ e or Y e gametes. Therefore, the F1 females will have the genotype Xsd Xsd+ e e+ and the F1 males will have the genotype Xsd Y e e+.

If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a Xsd Xsd e e genotype and appear in a 1/16 proportion.

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2 years ago

Why do you praise role of decomposers​

Why do you praise role of decomposers